Speed of the man = (2x 5/8) m/s = 5/9 m/s
Let the speed of the train be x m/s
x- 5/9 = 100/9
x= 100/9 + 5/9+ 105/9 =35/9 m/s
Let the speed of the car be y m/s .
35/3 + y = 100/3
y= 100/3 -35/3 =65/3 m/s
So, speed of the car =( 65/ 3 X 18/5) km/h =78 km/h
Let the length of the train =x m and speed of the train = y m/s Then,
y= x/10 and y= x+300/25
On solving Eqs. (i) and (ii), we got
= 25x= 10x +3000
= 15x = 3000 = x =200
So, the length of the train is 200 m.
Speed of the train
= Length of the (train + stationary object) / Time taken to cross the stationary object
Let the length of the bridge be x.
Speed of the train = 90 km/h = 90X(5/18) m/s = 25 m/s
25 = 130+x/20
x= (25X 20 - 130) m
= 370 m
Distance covered by the goods train in
3 h = (60X3) km = 180 km
Relative speed =(90-60) km/h =30 km/h
Let X be the time taken for the express train to overtake the goods train.
Then, 30= 180/x
X = (180/30) h = 6 h
Distance from A =(90X60) km =540 km